Update Automated MNLP evaluation report (2026-05-22)

EVAL_REPORT.md

@@ -2,7 +2,7 @@
 
 - **Model repo:** [`cs-552-2026-thinkinsidethebox/general_knowledge_model`](https://huggingface.co/cs-552-2026-thinkinsidethebox/general_knowledge_model)
 - **Owner(s):** group **thinkinsidethebox**
-- **Generated at:** 2026-05-21T03:28:21+00:00 (UTC)
+- **Generated at:** 2026-05-22T03:04:12+00:00 (UTC)
 - **Pipeline:** [mnlp-project-ci](https://github.com/eric11eca/mnlp-project-ci)
 
 _This PR is opened automatically by the course CI. It is **non-blocking** — you do not need to merge it. The next nightly run will refresh this file._
@@ -12,7 +12,7 @@ _This PR is opened automatically by the course CI. It is **non-blocking** — yo
 | Benchmark | Accuracy | Status |
 |---|---:|---|
 | Math | — | not run |
-| Knowledge | 0.3200 | ok |
+| Knowledge | 0.3500 | ok |
 | Multilingual | — | not run |
 | Safety | — | not run |
 
@@ -24,9 +24,9 @@ _Prompts are intentionally omitted to avoid revealing benchmark contents. For mu
 
 **Correct** (1 shown)
 
-- **reference**: `B`
+- **reference**: `F`
 - **overall** (1/1 completions correct)
-- **extracted** (✓): `B`
+- **extracted** (✓): `F`
 - **completion**:
 
     ```text
@@ -34,14 +34,65 @@ _Prompts are intentionally omitted to avoid revealing benchmark contents. For mu
     
     </think>
     
-    \boxed{B}
+    We are given the surface area of a human body as:
+    
+    $$
+    S = 0.1091 w^{0.425} h^{0.725}
+    $$
+    
+    and told that the measurement errors for both $w$ and $h$ are no greater than $2\%$. We are to estimate the largest possible percentage error in the computed value of $S$.
+    
+    ---
+    
+    ### Step 1: Compute the relative error in $S$
+    
+    We first compute the relative error in $w$ and $h$, and then combine them using the properties of logarithms.
+    
+    $$
+    \frac{\Delta S}{S} \approx \left( \frac{\partial S}{\partial w} \frac{\Delta w}{w} + \frac{\partial S}{\partial h} \frac{\Delta h}{h} \right)
+    $$
+    
+    We compute the partial derivatives:
+    
+    $$
+    \frac{\partial S}{\partial w} = 0.1091 \cdot 0.425 w^{-0.575} h^{0.725}
+    $$
+    $$
+    \frac{\partial S}{\partial h} = 0.1091 \cdot 0.725 w^{0.425} h^{-0.275}
+    $$
+    
+    Now we compute the relative error:
+    
+    $$
+    \frac{\Delta S}{S} \approx 0.425 \cdot \frac{\Delta w}{w} + 0.725 \cdot \frac{\Delta h}{h}
+    $$
+    
+    Since the errors are no greater than $2\%$, we use:
+    
+    $$
+    \frac{\Delta w}{w} \leq 0.02, \quad \frac{\Delta h}{h} \leq 0.02
+    $$
+    
+    Then:
+    
+    $$
+    \frac{\Delta S}{S} \leq 0.425 \cdot 0.02 + 0.725 \cdot 0.02 = 0.0085 + 0.0145 = 0.023 = 2.3\%
+    $$
+    
+    ---
+    
+    ### Final Answer
+    
+    $$
+    \boxed{F}
+    $$
     ```
 
 **Incorrect** (1 shown)
 
 - **reference**: `C`
 - **overall** (0/1 completions correct)
-- **extracted** (✗): `H`
+- **extracted** (✗): `D`
 - **completion**:
 
     ```text
@@ -49,5 +100,5 @@ _Prompts are intentionally omitted to avoid revealing benchmark contents. For mu
     
     </think>
     
-    \boxed{H}
+    \boxed{D}
     ```